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BASIC ELECTRICITY-OBJ
01-10: BABDAABDCC
11-20: CABADCCCDB
21-30: CBADCCDDBB
31-40: BADAABCBCB
41-50: DBABCACACB
Solved by Examking.netCompleted!!!
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BASIC ELECTRICITY- ESSAY-ANSWERS
(3a)
To calculate the total power consumed, we need to sum the power consumption of each type of accessory. Lamps: 10 lamps * 60 watts/lamp = 600 watts Ceiling Fans: 5 fans * 75 watts/fan = 375 watts Air Conditioners: 5 air conditioners * 746 watts/air conditioner = 3730 watts Electric Cooker: 1 cooker * 2500 watts/cooker = 2500 watts Total Power Consumption: 600 watts + 375 watts + 3730 watts + 2500 watts = 7205 watts, or 7.205 kW.
(3b)
To determine the energy meter reading after 5 hours, we need to calculate the total energy consumed in kilowatt-hours (kWh). Total Energy Consumption: 7.205 kW * 5 hours = 36.025 kWh Therefore, the energy meter reading at the 5-hour mark will be 36.025 kWh, assuming the meter started at 0 kWh.
(3c)
(i)Overheating:
(ii)Voltage Drop:
(iii)Safety Hazard:
(iv)Cable Degradation:
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(7ai)
(i) Reduces equipment failure: Regular maintenance helps identify and fix potential problems before they cause breakdowns.
(ii) Extends equipment lifespan: Preventive care ensures devices operate efficiently for a longer time.
(7aii)
(i) Worn-out or faulty capacitor, which can prevent the fan from starting or running at proper speed.
(ii) Damaged or loose wiring, which may lead to malfunction or electrical hazards.
(7bi)
Possible Cause of the Fault:
The possible cause is a short circuit or insulation failure in the kettle, causing the metal body to become energized.
(7bii)
Corrective Action:
Disconnect the kettle from power immediately and have it inspected and repaired or replaced by a qualified electrician.
(7biii)
Preventive Measure:
Regular inspection and maintenance of electrical appliances, including checking for worn-out insulation, damaged cords, or faulty grounding, can prevent such faults.
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(5a)
Draw the diagram
(5b)
(PICK ANY ONE)
(i) Voltage Step-Up: Increases voltage at the generation end for efficient long-distance transmission (reduces current and power losses).
(ii) Voltage Step-Down: Decreases voltage at the distribution end to safe levels suitable for homes and industries.
(iii) Impedance Matching: Helps in matching impedance between components for maximum power transfer and system efficiency.
(iv) Electrical Isolation: Provides isolation between different parts of the system to enhance safety and system protection.
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(2a)
Impedance (Z) is the total opposition to the flow of alternating current (AC) in a circuit, which combines both resistance (R) and reactance (X).
(2b)
(Draw the diagram)
(2ci)
Given:
Output RMS Voltage Vrms = 220V
Maximum voltage (Vmax) = Vrms x (√2)
Vmax = 220 x (√2)
Vmax = 220 x 1.414
Vmax = 310.88V
(2cii)
Average value (Vavg) = (2/π) x Vmax
Vavg = (2/π) x 310.88
Vavg = 0.636 x 310.88
Vavg = 197.25V
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COMPLETED!!!